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Assign Multiple Variables

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Zach
Zach el 28 de Sept. de 2011
Comentada: Walter Roberson el 15 de Abr. de 2023
I have a array for example [1,2,3,4]. I want to assign a variable to each number in the array such that a=1, b=2, c=3, and d=4. I know I can do each one separately but I want to know if it is possible to this in one line.
  1 comentario
Image Analyst
Image Analyst el 29 de Sept. de 2011
Kind of reminded me of the FAQ: http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F though I'm not saying you don't have a valid reason for doing that - you may well have.

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Walter Roberson
Walter Roberson el 28 de Sept. de 2011
It is not possible in one statement. It is possible in two statements, which you could combine on one line.
t = num2cell([1,2,3,4]);
[a,b,c,d] = deal(t{:});
  8 comentarios
Fangjun Jiang
Fangjun Jiang el 14 de Abr. de 2023
t = num2cell([1,2,3,4]);
[a,b,c,d] = deal(t{:})
a = 1
b = 2
c = 3
d = 4
[a,b,c,d] = t{:}
a = 1
b = 2
c = 3
d = 4
Walter Roberson
Walter Roberson el 15 de Abr. de 2023
Back in 2011 it was not possible in one statement, at least not without an inline subsref(). A few years ago, however, a hack became available:
[a,b,c,d] = struct('x', num2cell([1,2,3,4])).x
a = 1
b = 2
c = 3
d = 4

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Más respuestas (4)

Raziman Thottungal Valapu
Raziman Thottungal Valapu el 1 de Oct. de 2020
It is now possible to do this in one line cleanly
[a,b,c] = deal(1, "test", [1:5])
Gives me
a =
1
b =
"test"
c =
1 2 3 4 5
As expected
  1 comentario
Stephen23
Stephen23 el 1 de Oct. de 2020
@Raziman Thottungal Valapu: no, that is not what the question is about. The question specifies that there is only one input array, but your code uses multiple separate inputs to deal. Not the same thing at all.

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Jeff Miller
Jeff Miller el 15 de Ag. de 2018
matsplit does this.
  2 comentarios
Stephen23
Stephen23 el 15 de Ag. de 2018
+1 neat
Brent F
Brent F el 19 de Jun. de 2021
Much cleaner than deal(a(1), a(2), a(3), a(4), ...)

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Viktor
Viktor el 1 de Sept. de 2018
Editada: Viktor el 1 de Sept. de 2018
The one-liner I have been using is the following:
[a,b,c,d] = feval(@(x) x{:}, num2cell([1,2,3,4]));
(Don't claim it is my original idea, just felt it belongs to this thread. If it is posted elsewhere feel free to link it.)
  2 comentarios
Daniel Birch
Daniel Birch el 12 de Sept. de 2018
Additionally, you can replace num2cell with any cell array of the right size, even one containing multiple data types. For example,
[a,b,c,d] = feval(@(x) x{:}, {rand(2), 5, 'hello', pi});
a
a =
0.9502 0.4387
0.0344 0.3816
b
b =
5
c
c =
hello
d
d =
3.1416
Stephen23
Stephen23 el 12 de Sept. de 2018
Editada: Stephen23 el 12 de Sept. de 2018
That is just subsref wrapped up in an anonymous function, which is then called by feval.
Here it is with subsref called directly:
>> [a,b,c,d] = subsref({rand(2), 5, 'hello', pi}, substruct('{}',{':'}))
a =
0.103676 0.814128
0.208758 0.092132
b = 5
c = hello
d = 3.1416

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Dan Erwin
Dan Erwin el 14 de Abr. de 2023
Editada: Walter Roberson el 14 de Abr. de 2023
The thing we are trying to do is emulate the very useful Python idiom e.g.
a,b,c,d = [1,2,3,4]
In Matlab, if you create a function assignList.m as follows:
function varargout = assignList( inputArray )
for i = 1:length( inputArray)
varargout{i} = inputArray(i);
end
end
then you can do for example
[a,b,c,d] = assignList( [1,2,3,4] )
  4 comentarios
Fangjun Jiang
Fangjun Jiang el 14 de Abr. de 2023
@Stephen23, not with array input directly. See my comments at the answer by @Walter Roberson. My point is that this funciton is uncessary. Plus, I can't resist the "Deal or No deal" pun, now that I realized it.
Dan Erwin
Dan Erwin el 15 de Abr. de 2023
I would not have written my post if I had noticed the earlier answer which recommended the contributed function matsplit, which is similar to mine but is more flexible when using multidimensional arrays.

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